QSize() will construct an invalid size. An invalid size has width and
height set to -1. In other words, QSize() != QSize(0, 0). This can create
issues when computing the bounding rect of a surface that has invisible
subsurfaces.

For example, if the subsurface rect is QRect(0,0 -1x-1), the top-left
corner of the bounding rect will be affected.

In order to make computation of the bounding rect robust, initialize the
surface size to 0 explicitly.

BUG: 454535