Provably, if two integers can fit in 31 bits each, the result of their
multiplication is expressible in 62 bits (let alone 63 available). So,
this should be safe. And the division can't do much harm: the divisor
is always at least 1, and worst case scenario — it would be so big that
the overall results becomes zero.

This code still assumes that the allowed brightness values can fit in 32
bits int, which is not totally unreasonable so far.

BUG: 454161